"Crash" Jackson approaches a rotary in his 3,500 kg Maserati. It's radius of curvature is 95meters but his speed is 25 m/s. What is his acceleration in m/sec/sec and find his coefficient of friction between his tires and the road?
a = v^2/r
µ = Ff/Fn = (v^2/r)/g
(m's cancel)
a=6.6m/s^2?
I'm still confused with m I got a negative number which is wrong
m=.00192?
To find Crash Jackson's acceleration, we need to determine the centripetal acceleration he's experiencing while going around the rotary.
The centripetal acceleration is given by the formula:
a = v^2 / r
where v is the speed and r is the radius of curvature.
Plugging in the given values:
v = 25 m/s
r = 95 meters
a = (25 m/s)^2 / 95 meters
= 625 m^2/s^2 / 95 meters
≈ 6.579 m/s^2
Therefore, Crash Jackson's acceleration is approximately 6.579 m/s^2.
Now, to find the coefficient of friction between his tires and the road, we'll use the following formula:
a = μ * g
where μ is the coefficient of friction and g is the acceleration due to gravity (approximately 9.8 m/s^2).
Rearranging the formula, we have:
μ = a / g
Plugging in the value of a we found earlier:
a = 6.579 m/s^2
g = 9.8 m/s^2
μ = 6.579 m/s^2 / 9.8 m/s^2
≈ 0.6712
Therefore, the coefficient of friction between Crash Jackson's tires and the road is approximately 0.6712.