Meeta is four years older than Sunitha. After eight years, the sum of their ages will be three times that of their present ages. What is the age of Meeta?
m = s+4
m+8 + s+8 = 3(m+s)
or,
m-s = 4
m+s = 8
m = 6
Well, isn't this an age-old math problem? Pun intended! Let's solve it using our funny bones!
Let's call Sunitha's age "S" and Meeta's age "M." According to the problem, Meeta is four years older than Sunitha, so M = S + 4.
After eight years, their ages will be M + 8 and S + 8. And the given information states that the sum of their ages after eight years will be three times the sum of their present ages. In equation form, we have:
(M + 8) + (S + 8) = 3(M + S)
Now, let's substitute M with S + 4:
(S + 4 + 8) + (S + 8) = 3(S + (S + 4))
Simplifying the equation, we get:
2S + 20 = 6S + 12
Rearranging the equation:
4S = 8
Dividing both sides by 4:
S = 2
So, Sunitha is currently 2 years old. To find Meeta’s age, we substitute this value back into the equation M = S + 4:
M = 2 + 4
M = 6
Therefore, Meeta is 6 years old. Voila!
Let's represent Sunitha's present age as x.
According to the statement, Meeta is four years older than Sunitha, so Meeta's present age can be represented as x + 4.
After eight years, Sunitha's age will be x + 8 and Meeta's age will be (x + 4) + 8 = x + 12.
The sum of their ages after eight years will be (x + 8) + (x + 12) = 3(x + x + 4) = 3(2x + 4).
Simplifying the equation, we get 2x + 20 = 3(2x + 4).
Expanding the brackets, we have 2x + 20 = 6x + 12.
Subtracting 2x from both sides, we get 20 = 4x + 12.
Subtracting 12 from both sides yields 8 = 4x.
Dividing both sides by 4 gives us x = 2.
Therefore, Sunitha's present age is 2 years.
Meeta's present age can be found by adding 4 to Sunitha's age: 2 + 4 = 6.
Therefore, Meeta's age is 6 years.
To find the age of Meeta, let's assign variables for their ages. Let's say the present age of Sunitha is "x" years.
According to the given information, Meeta is four years older than Sunitha, so Meeta's present age can be represented as x + 4 years.
After eight years, Sunitha's age will be x + 8 years, and Meeta's age will be (x + 4) + 8 years.
The sum of their ages after eight years is three times the sum of their present ages. Mathematically, we can represent this as:
(x + 8) + ((x + 4) + 8) = 3(x + (x + 4))
Simplifying the equation:
2x + 20 = 3(2x + 4)
Expanding the right side of the equation:
2x + 20 = 6x + 12
Rearranging the equation:
6x - 2x = 20 - 12
4x = 8
Dividing both sides by 4:
x = 2
Therefore, Sunitha's present age is 2 years.
To find Meeta's present age, we substitute the value of x back into the equation:
Meeta's present age = x + 4 = 2 + 4 = 6 years.
Therefore, Meeta is 6 years old.