Write and balance the equation for the reaction between nitric acid and potassium iodide. The products are potassium nitrate, iodine, nitrogen monoxide, and water.
2HNO3 + KI = KNO3 + I + 2NO + H2O
(Did I write the equation correctly?)
Hang on, the nitrogens don't match. Also Iodine does not exist as I, it is diatomic (I2) try this...
6 KI + 8 HNO3 --> 6 KNO3 + 2 NO +3 I2 + 4 H2O
Yes, you have correctly written the balanced equation for the reaction between nitric acid (HNO3) and potassium iodide (KI) to form potassium nitrate (KNO3), iodine (I), nitrogen monoxide (NO), and water (H2O).
2HNO3 + 2KI = 2KNO3 + I2 + 2NO + H2O
Yes, you wrote the equation correctly.
To balance the equation, you need to make sure that the number of atoms of each element is equal on both sides of the equation. Let's go through the process step-by-step:
1. Start by looking at the number of atoms for each element on the left side:
- Nitrogen (N): 2 atoms in HNO3.
- Hydrogen (H): 2 atoms in HNO3.
- Oxygen (O): 6 atoms in HNO3.
2. Now, let's examine the elements on the right side:
- Nitrogen (N): 1 atom in KNO3 and 2 atoms in 2NO.
- Hydrogen (H): 2 atoms in H2O.
- Oxygen (O): 6 atoms in KNO3, 2 atoms in I2 and 2 atoms in 2NO.
3. To balance the nitrogen atoms, multiply the coefficient of KNO3 by 2:
2HNO3 + KI = 2KNO3 + I2 + 2NO + H2O
4. Next, balance hydrogen atoms by adding a coefficient of 4 in front of HNO3:
4HNO3 + KI = 2KNO3 + I2 + 2NO + H2O
5. Oxygen atoms are already balanced.
6. Finally, balance the iodine atoms by adding a coefficient of 2 in front of KI:
4HNO3 + 2KI = 2KNO3 + I2 + 2NO + H2O
Now the equation is balanced, with the same number of each element on both sides.