An electron traveling at 7.00 x 10^6 m/s enters and passes through a parallel plate capacitor. determine the electric field generated by the capacitor. note that the electron just clears the corner of the positive plate.
PLEASE SHOW ALL WORK!!!
I suspect some vital info is not posted, such as the distance between the plates, the horizonal length of the path of the plates.
I am guessing the total deflection is the distance between the plates.
The distance of the parallel plate capacitor is 2.0 cm and the height it 1.5mm.
ok, the force on the electron is E*e, and it is deflected .0015m.
Figure the time it took to go through the field .02m at the given velocity. So you know time, and force, and distance deflected.
F=ma a=F/m
distance=1/2 a*t =1/2 Ee/m * t
solve for E
ok, the force on the electron is E*e, and it is deflected .0015m.
Figure the time it took to go through the field .02m at the given velocity. So you know time, and force, and distance deflected.
F=ma a=F/m
distance=1/2 a*t =1/2 Ee/m * t
solve for E
OOPs,
distance=1/2 a t^2=1/2 Ee/m*t^2
solve for E
Thanks, that clears it up a little. But would you be able to possibly plug in the numbers so that I could get a clearer image/reasoning of the answer?
That would be greatly appreciated!
To determine the electric field generated by the parallel plate capacitor, we need to use the velocity of the electron and its distance from the plates.
1. Calculate the acceleration of the electron:
The electron experiences an acceleration due to the electric field as it passes through the capacitor. This acceleration can be calculated using the equation:
acceleration = (change in velocity) / (time taken)
Since the electron is traveling at a constant velocity, the change in velocity is 0. Therefore, the acceleration is 0, and the speed of the electron remains constant.
2. Calculate the time taken to pass through the capacitor:
To find the time taken, we need to know the distance traveled by the electron. From the given information, it just clears the corner of the positive plate. Let's assume this distance is "d".
time taken = distance / velocity
Since the electron clears the corner, the distance is equal to the distance between the plates of the capacitor.
3. Determine the distance between the plates:
Unfortunately, the distance between the plates is not given in the question. Therefore, we cannot directly calculate the exact electric field. However, I can explain the formula for the electric field based on the distance between the plates.
The electric field between the parallel plates of a capacitor is given by:
electric field (E) = voltage (V) / distance between plates (d)
The voltage (V) across the capacitor should be provided in the question or given as a separate value. If you have the voltage value, you can substitute it into the formula along with the distance between the plates to calculate the electric field.
Please provide the voltage value or any additional information to proceed with the calculation.