The perimeter of a rectangle is 21 inches. What is the measure of its width if its length is 3 inches greater than its width?..... Please help me solve this question...
P=2W+2L
but W=L-3
21=2(L-3)+2L
solve for L first.
Let's represent the width of the rectangle as "w" inches.
According to the given information, the length of the rectangle is 3 inches greater than its width. So, the length can be represented as "w + 3" inches.
The perimeter of a rectangle is calculated by adding the lengths of all four sides. In this case, the perimeter is 21 inches.
The formula for the perimeter of a rectangle is 2(length + width).
Plugging in the given values, we get:
2(w + w + 3) = 21
Simplifying the equation:
2(2w + 3) = 21
4w + 6 = 21
4w = 21 - 6
4w = 15
Dividing both sides of the equation by 4:
w = 15 / 4
w = 3.75
Therefore, the width of the rectangle is 3.75 inches.
To solve this question, we need to set up an equation based on the given information. Let's denote the width of the rectangle as 'w' (in inches) and the length as 'l' (in inches).
We are given that the length is 3 inches greater than the width, so we can say:
l = w + 3
The perimeter of a rectangle is given by the formula:
Perimeter = 2(length + width)
Since we know the perimeter is 21 inches, we can substitute the values into our equation:
21 = 2(w + 3 + w)
Simplifying the equation, we have:
21 = 2(2w + 3)
21 = 4w + 6
Subtracting 6 from both sides, we get:
15 = 4w
Finally, dividing both sides by 4, we find:
w = 15/4 or 3.75 inches
Therefore, the width of the rectangle is 3.75 inches.