An artist is painting a large mural comprised of different sizes squares. She wants to pain one magenta square that is as large as possible, but she only has one can of magenta paint. If the can of paint can cover 220 square feet, what is the side of the largest square that she can paint if she needs to apply 2 coats of paint?
Round to the nearest whole number.
110 sq ft pre coat, so side=sqrt(110)=10.5 ft
To find the side length of the largest square that can be painted with the given amount of paint, we need to consider the area covered by each coat of paint.
Since the can of paint can cover 220 square feet, and two coats of paint are needed, the total area that can be covered is 220 * 2 = 440 square feet.
Now, let's assume that the side length of the largest square that can be painted is x. The area of a square is given by the formula A = x^2.
We need to find the value of x such that x^2 is as close to 440 as possible without exceeding it.
To do this, we can start by trying different values of x. We can start with x = 20, which gives us an area of 20^2 = 400.
Since 400 is less than 440, we can try a larger value of x. Let's try x = 21, which gives us an area of 21^2 = 441.
Since 441 is larger than 440, we can conclude that the largest square that can be painted is the one with a side length of 20 feet (rounded to the nearest whole number).
Therefore, the artist can paint a square with a side length of 20 feet, which is the largest size possible with the given amount of paint.