A photon of light has a wavelength of about 600 nm (1nm = 1 x 10-9 m). What is the energy of this photon of light?
how do I solve this step by step?
your equation is:
E = (hc/Lambda)
E = energy
h = planck's constant (6.626 × 10^-34 joule·s)
c = speed of light (2.998 × 10^8 m/s)
lambda = wavelength
1)
h*c = 1.99 × 10^-25 joules-m
note: when dealing with photons and electrons, we usually use electric volts (eV) instead of Joules(J) as our units.
1eV = 1.602 × 10-19 J
Therefore:
hc = (1.99 × 10^-25 joules-m) × (1ev/1.602 × 10^-19 joules) = 1.24 × 10^-6 eV-m
hc = 1.24 * 10^6 eV-M
2)
Change hc to µm to compensate for the wavelenth
(1.24 * 10^6eV-m) * (10^6 µm/ m) = 1.24 eV-µm
hc = 1.24
3)
change 600nm to µm (micro meter)
600nm = 0.6µm
E = (1.24µm/0.6µm)
E = approx. 31/15eV
To calculate the energy of a photon, you can use the equation:
Energy (E) = Planck's constant (h) * speed of light (c) / wavelength (λ)
Step 1: Convert the wavelength from nanometers (nm) to meters (m).
Given: 1 nm = 1 x 10^-9 meters
So, the wavelength (λ) = 600 nm = 600 x 10^-9 m
Step 2: Determine the value of Planck's constant (h) and the speed of light (c).
Planck's constant (h) = 6.62607015 x 10^-34 J⋅s
Speed of light (c) = 2.998 x 10^8 m/s
Step 3: Substitute the values into the equation to calculate the energy.
E = (6.62607015 x 10^-34 J⋅s) * (2.998 x 10^8 m/s) / (600 x 10^-9 m)
Step 4: Simplify the equation.
E = 0.0131 J
Therefore, the energy of a photon with a wavelength of 600 nm is approximately 0.0131 Joules.