The length of a rectangular garden is one foot less than five times its width. The area is 18sl square feet. Find the width.

L = 5 w - 1

A = L w = (5w-1)w

A = 5 w^2 - w = 18 of whatever sl is

5 w - 1 w - 18 = 0

w = [ 1 +/- sqrt(1+360) ]/10
= [

[ 1 +/- 19]/10

use
w = 2
then L = 9

To solve this problem, we can create an equation based on the given information and then solve for the unknown variable, which is the width of the rectangular garden.

Let's start by assigning a variable to the width of the garden. Let's call it "w" (in feet).

According to the problem, the length of the garden is one foot less than five times its width. So, the length can be represented by the expression "5w - 1".

The area of a rectangle is given by the formula: Area = Length * Width. In this case, the area is given as 18 square feet. So, we can write the equation:

Area = Length * Width
18 = (5w - 1) * w

Now, let's solve this equation for "w".

18 = (5w - 1) * w
18 = 5w^2 - w
0 = 5w^2 - w - 18

To solve this quadratic equation, we can factor it or use the quadratic formula. In this case, let's use the quadratic formula:

w = (-b ± √(b^2 - 4ac)) / 2a

Plugging in the values for a, b, and c from our equation (5w^2 - w - 18 = 0), we get:

w = (1 ± √(1^2 - 4(5)(-18))) / (2(5))
w = (1 ± √(1 + 360)) / 10
w = (1 ± √361) / 10
w = (1 ± 19) / 10

Simplifying further, we have:

w = (1 + 19) / 10 OR w = (1 - 19) / 10
w = 20 / 10 OR w = -18 / 10
w = 2 OR w = -1.8

Since we are dealing with measurements, the width cannot be negative. Therefore, the width of the rectangular garden is 2 feet.