find the slope of a line that is perpendicular to the line containing the points (–2 –1) and (2 –3)
A.) m=-2
B.) m=2
C.) m=-1/2
D.) m=1/2
slope of line with points: (-1+3)/(-2-2)=-1/2
line perpendicular then
m=2
What is the slope of a line perpendicular to the line containing the coordinates (12, -2) and (2, -6)?
To find the slope of a line perpendicular to another line, we need to use the fact that the slopes of perpendicular lines are negative reciprocals of each other.
Given the points (–2, –1) and (2, –3), we can find the slope of the line that contains these points by using the formula:
m = (y2 - y1) / (x2 - x1)
Plugging in the values from the given points, we get:
m = (-3 - (-1)) / (2 - (-2))
= (-3 + 1) / (2 + 2)
= -2 / 4
= -1/2
Therefore, the slope of the line containing the points (–2, –1) and (2, –3) is -1/2.
Since the slope of a line perpendicular to this line is the negative reciprocal of -1/2, we can find the slope of the perpendicular line by taking the reciprocal and changing the sign:
m_perpendicular = -1 / (-1/2)
= -1 * (-2/1)
= 2
So, the slope of the line that is perpendicular to the line containing the points (–2, –1) and (2, –3) is 2.
Therefore, the answer is B.) m = 2.