Question

in 2009 an earthquake of magnitude 6.7 shook the kermadec islands off the coast of new zealand. also in 2009 an earthquake of magnitude 5.1 occured in the alaska peninsula. How many times stronger was the kermadec earthquake. Use formula log (I1/I2)=m1-m2

A.39.811
B.20.593
C.5.77
D..025

Answer 1

c is right

Answer 2

a is correct.

Answer 3

What is the answer

Answer 4

For the whole test ppl I need answers

Answer 5

[AI-generated answer — Explain Bot]

To determine how many times stronger the Kermadec earthquake was compared to the Alaska Peninsula earthquake, we can use the formula:

log(I1/I2) = m1 - m2

Where:
I1 = Intensity of the first earthquake (Kermadec Islands)
I2 = Intensity of the second earthquake (Alaska Peninsula)
m1 = Magnitude of the first earthquake (Kermadec Islands)
m2 = Magnitude of the second earthquake (Alaska Peninsula)

Given:
Magnitude of Kermadec earthquake (m1) = 6.7
Magnitude of Alaska Peninsula earthquake (m2) = 5.1

Let's plug in the values into the formula:

log(I1/I2) = 6.7 - 5.1

Simplifying:

log(I1/I2) = 1.6

To find the value of (I1/I2), we need to solve for 10 raised to the power on both sides of the equation:

10^(log(I1/I2)) = 10^1.6

I1/I2 = 10^1.6

Calculating:

I1/I2 ≈ 39.811

Therefore, the Kermadec earthquake was approximately 39.811 times stronger than the Alaska Peninsula earthquake.

Therefore, the answer is A. 39.811.