A napkin ring is being made of cast silver. It has the shape of a cylinder 1.25 inches high, with a cylindrical hole 2 inch in diameter and a thickness of 1/16 inch. How many ounces of silver are needed? [silver weighs 6 ounces per cubic inch]

Yes math

inside radius = 1 inch

outside radius = 1.0625 inch

volume = 1.25 (pi)(1.0625^2-1)

= .5062 in^3

mass = 6 * .5062 = 3.04 oz

I don't know the answer I need help

To find out how many ounces of silver are needed for the napkin ring, we need to calculate the volume of the silver used.

The napkin ring can be thought of as a solid cylinder with a cylindrical hole in it. The outer part of the napkin ring is a cylinder with a height of 1.25 inches and a diameter of 2 inches. The inner part of the napkin ring is also a cylinder, but with a smaller diameter representing the hole.

To find the volume of the napkin ring, we need to subtract the volume of the hole from the volume of the outer cylinder.

Volume of the outer cylinder = π * (radius of outer cylinder)^2 * height of outer cylinder
Volume of the hole = π * (radius of hole)^2 * height of outer cylinder

Given:
Height of outer cylinder (h1) = 1.25 inches
Diameter of outer cylinder (d1) = 2 inches
Thickness of the napkin ring (t) = 1/16 inch

First, let's calculate the radius of the outer cylinder:
Radius of outer cylinder (r1) = d1/2 = 2 inches / 2 = 1 inch

Next, let's find the radius of the hole:
Since the hole is the same size as the inner part of the napkin ring, i.e., it has the same thickness of 1/16 inch, the radius of the hole will be the radius of the outer cylinder minus the thickness:
Radius of hole (r2) = r1 - t = 1 inch - 1/16 inch = 15/16 inch

Now, let's calculate the volume:

Volume of the outer cylinder = π * (r1)^2 * h1
Volume of the outer cylinder = π * (1 inch)^2 * 1.25 inches

Volume of the hole = π * (r2)^2 * h1
Volume of the hole = π * (15/16 inch)^2 * 1.25 inches

To find the volume of the silver used, subtract the volume of the hole from the volume of the outer cylinder:

Volume of silver = Volume of the outer cylinder - Volume of the hole

Finally, convert the volume of silver to ounces by multiplying it by the density of silver, which is 6 ounces per cubic inch:

Weight of silver = Volume of silver * Density of silver

Now, we can plug in the values and calculations into the formula:

Volume of silver = ( π * (1 inch)^2 * 1.25 inches ) - ( π * (15/16 inch)^2 * 1.25 inches )
Weight of silver = Volume of silver * 6 ounces per cubic inch

By evaluating these calculations, you will find the amount of silver needed for the napkin ring in ounces.