A silo is filled at a constant rate for a total of 10 hours.
Number of Hours---Amt of Corn(cu ft)
0----------------- 0-------------
3------------------2475---------
5------------------4125----------
8------------------6600----------
Enter the "percent" of the silo that is filled with corn at 10 hours.
Is the answer 82.5 or 91 percent?
The fill rate is clearly 825 ft^3/hr
At 10 hours, that will be 8250 ft^3.
no idea of the percent filled. How big is the silo?
To find the percent of the silo that is filled with corn at 10 hours, we need to compare the amount of corn filled to the maximum capacity of the silo.
From the given data, we can see that in 10 hours, the amount of corn filled in the silo is 6600 cubic feet.
To find the maximum capacity of the silo, we need to find the rate at which it is filled. We can do this by finding the average rate of filling per hour.
Total amount of corn filled in 10 hours = 6600 cubic feet
Average rate of filling per hour = Total amount of corn filled / Number of hours = 6600 cubic feet / 10 hours = 660 cubic feet per hour
Now, since the filling rate is constant, we can calculate the maximum capacity of the silo by multiplying the filling rate per hour by 10 hours.
Maximum capacity of the silo = Filling rate per hour * 10 hours = 660 cubic feet per hour * 10 hours = 6600 cubic feet
Therefore, the silo is filled to its maximum capacity of 6600 cubic feet at 10 hours.
To find the percentage filled at 10 hours, we can divide the amount of corn filled by the maximum capacity and multiply by 100.
Percentage filled at 10 hours = (Amount of corn filled / Maximum capacity) * 100 = (6600 cubic feet / 6600 cubic feet) * 100 = 100%
So, the silo is 100% filled with corn at 10 hours.
To determine the percentage of the silo that is filled with corn at 10 hours, we need to calculate the amount of corn filled at 10 hours.
Based on the given information, we can see that in the first 3 hours, 2475 cubic feet of corn was filled. In the next 2 hours, an additional 4125 - 2475 = 1650 cubic feet of corn was filled. And finally, in the last 3 hours, an additional 6600 - 4125 = 2475 cubic feet of corn was filled.
To find the amount of corn filled in the last 2 hours, we can calculate the average rate of corn being filled per hour:
Average rate = (1650 cubic feet of corn filled) / (2 hours) = 825 cubic feet per hour
Now, we can calculate the corn filled in the last 2 hours:
Corn filled in the last 2 hours = (Average rate) * (2 hours) = 825 * 2 = 1650 cubic feet
Adding up all the corn-filled amounts:
Corn filled at 10 hours = 2475 + 1650 + 2475 = 6600 cubic feet
Since the total capacity of the silo is not mentioned, we cannot calculate the percentage directly. However, if you have the total capacity of the silo, you can use the following formula to find the percentage filled:
Percentage filled = (Corn filled at 10 hours / Total capacity of the silo) * 100%
Please provide the total capacity of the silo in cubic feet to find the percentage filled.