Assuming an object at infinity, a person has far points of 5.2 m from the right eye and 6.2 m from the left eye. Describe the lens required (diopters) as seen in a prescription for the refractive power of each corrective contact lens.
Ayyee, fellow EP101 student
@ Mu fellow ep102 student, WHY DIDN'T YOU ANSWER THE QUESTION???????
To calculate the refractive power (diopters) of the corrective contact lens for each eye, we need to use the concept of focal length.
Focal length (f) is the distance between the lens and the point where parallel rays of light converge or appear to diverge from. It is denoted in meters.
The formula to calculate the refractive power (P) of a lens in diopters is given by:
P = 1 / f
Given that the person has far points of 5.2 m from the right eye and 6.2 m from the left eye, we can find the focal length for each eye and then calculate the refractive power in diopters.
For the right eye:
The far point distance for the right eye is 5.2 m. To find the focal length, we use the formula:
1 / f = 1 / object distance + 1 / image distance
Since the object is at infinity, the object distance is effectively infinite (∞). Therefore, the formula simplifies to:
1 / f = 0 + 1 / image distance
1 / f = 1 / 5.2
Solving for f, we find:
f = 5.2 m
Now, we can calculate the refractive power (P) using the formula:
P = 1 / f
P = 1 / 5.2
P = 0.1923 diopters (approximately)
So, the refractive power of the corrective contact lens for the right eye is approximately +0.1923 diopters.
Similarly, for the left eye:
The far point distance for the left eye is 6.2 m. Using the same calculations as above, we find that the focal length (f) is 6.2 m.
P = 1 / f
P = 1 / 6.2
P = 0.1613 diopters (approximately)
Therefore, the refractive power of the corrective contact lens for the left eye is approximately +0.1613 diopters.
In summary, the prescription for the refractive power of each corrective contact lens would be approximately +0.1923 diopters for the right eye and +0.1613 diopters for the left eye.