What mass of copper(ii) sulphate(GFM=159.5) is required to make 400cm3 of 0.5mol/l solution
To determine the mass of copper(II) sulfate required to make 400 cm³ of a 0.5 mol/L solution, you need to follow these steps:
Step 1: Understand the equation
The formula for calculating the number of moles is moles = volume (in liters) * concentration (in mol/L).
Step 2: Convert the volume to liters
Given that the volume is in cm³, you need to convert it to liters. Since 1 cm³ is equal to 1 mL and 1000 mL is equal to 1 L, the volume in liters is 400 cm³ / 1000 = 0.4 L.
Step 3: Calculate the number of moles
Using the formula moles = volume * concentration, you can substitute the values: moles = 0.4 L * 0.5 mol/L = 0.2 mol.
Step 4: Convert moles to grams
To convert moles to grams, you need to know the molar mass of copper(II) sulfate, which is given as 159.5 g/mol. Multiply the number of moles by the molar mass: grams = moles * molar mass = 0.2 mol * 159.5 g/mol = 31.9 g.
Therefore, to make a 0.5 mol/L solution with a volume of 400 cm³, you need 31.9 grams of copper(II) sulfate.