A double lens system is made of +35.0 cm lens (lens #1) and a -

26.0 cm lens (lens #2).
Lens #1 is placed at x = 0 cm on a meter stick and lens #2 is placed at x = 30.0 cm.
Where on the meter stick will the final image be formed when looking at a distant
object? s2"=f2(f1-d)/f1+f2-d
where d=30cm
=6.2cm is that the correct way to do this problem?

To find the position where the final image will be formed by the double lens system, you can use the lens formula:

1/s1 + 1/s2 = 1/f

Where:
s1 is the object distance,
s2 is the image distance, and
f is the focal length.

In this case, the object is at a distant location, so s1 can be considered as infinite (s1 ≈ ∞). Thus, 1/s1 ≈ 0.

The focal length of a lens is given by the formula:

1/f = 1/f1 + 1/f2

Where f1 and f2 are the focal lengths of lens #1 and lens #2, respectively.

Given that f1 = +35.0 cm and f2 = -26.0 cm, we can calculate 1/f:

1/f = 1/35.0 + 1/-26.0

Now, we can substitute the values into the lens formula:

0 + 1/s2 = (1/35.0 + 1/-26.0)

Simplifying this equation will give us the value of 1/s2. To find s2, we can inverse the calculated value of 1/s2:

s2 = 1 / (1/35.0 + 1/-26.0)

Now, let's calculate s2 using the given values:

s2 = 1 / ((1/35.0) + (1/-26.0))
≈ 6.2 cm

Hence, the final image will be formed approximately 6.2 cm from lens #2.

So, yes, your calculation is correct!