A sample of gas at 57C and 1.02atm occupies a volume of 2.20L. What volume would this gas occupy at 107C and 0.789atm?
T1 = 57 + 273
T2 = 107 + 273
P1 V1/T1 = P2 V2/T1
P1 V1/T1 = P2 V2/T2
1.02atm x 2,20L = 078atm x V2
330K 380K
2.244/ 330=.0068?
I'm lost.
T1 = 330
T2 = 380
1.02 * 2.2 / 330 = .789 * V2 /380
V2 = (1.02/.789)(380/330)(2.2)
= 3.28 L
note
expands as pressure goes down and expands as temperature goes up
so you can check if you have those ratios right.