If a certain amount of ideal gas occupies a volume 9.5 m3 with a pressure of 3.1 atm and temperature 5.4 oC on earth, what would be its volume on another planet, where the temperature is 5.3oC and the pressure is 7.4 atm ? The answer is in unit of m3
i wanna know the ans too
To solve this problem, we can use the ideal gas law, which states:
PV = nRT
Where:
P = pressure
V = volume
n = number of moles of gas
R = ideal gas constant
T = temperature
First, let's identify the given values:
On Earth:
P1 = 3.1 atm
V1 = 9.5 m^3
T1 = 5.4 + 273.15 = 278.55 K (converted from Celsius to Kelvin)
On the other planet:
P2 = 7.4 atm
T2 = 5.3 + 273.15 = 278.45 K
Since we are dealing with the same gas, the number of moles (n) and the ideal gas constant (R) remain constant. Therefore, we can rewrite the equation as:
(P1 * V1) / T1 = (P2 * V2) / T2
Now, we can rearrange the equation to solve for V2 (the volume on the other planet):
V2 = (P1 * V1 * T2) / (P2 * T1)
Substituting the given values:
V2 = (3.1 * 9.5 * 278.45) / (7.4 * 278.55)
Calculating the expression:
V2 = 9.943 m^3
Therefore, the volume of the gas on the other planet would be approximately 9.943 m^3.