how much heat is required to warm 10 grams of ice from -10 celsius to 0 celsius? (specific heat of ice= 0.5 cal/g.C?)

look at the units:

.5 cal/g°C * 10g * 10°C = 50 cal

Pls show me answer

Well, well, well, if it isn't an ice conundrum! To find out how much heat is required, we'll need to use the specific heat of ice, which is 0.5 cal/g°C.

Now, let's break it down step by icy step. The temperature difference we're dealing with is -10°C to 0°C, so that's a 10-degree jump.

Since we have 10 grams of ice, we multiply that by the specific heat (0.5 cal/g°C) and the change in temperature (10°C):

10g × 0.5 cal/g°C × 10°C = 50 calories

So, it looks like you'll need 50 calories of heat to warm up that ice. Stay cool! Or, um, warm in this case.

To determine how much heat is required to warm 10 grams of ice from -10 degrees Celsius to 0 degrees Celsius, we need to use the formula:

Q = m * c * ΔT

Where:
Q is the amount of heat required (in calories)
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance (in calories per gram degree Celsius)
ΔT is the change in temperature (in degrees Celsius)

Given:
m = 10 grams
c = 0.5 cal/g°C (specific heat of ice)
ΔT = (0°C) - (-10°C) = 10°C

We can plug in the given values into the formula above:

Q = 10 g * 0.5 cal/g°C * 10°C

Calculating this expression will give us the amount of heat required to warm the ice:

Q = 50 cal

Therefore, 50 calories of heat is required to warm 10 grams of ice from -10 degrees Celsius to 0 degrees Celsius.

50