A typical stone on the lowest level of the great pyramid in Egypt was a rectangular prism 5 feet long by 5 feet high by 6 feet deep and Weighed 15 tons what was the volume of the average stone how much does one cubic foot of the stone weigh
V = LWH
V = 5 * 5 * 6
V = 150 cubic feet
150/15 = _______ tons per cubic foot
150/15=10
so. the volume of this equation is 5ft x 5ft x 6ft = V and the weight was 15 tons. 5 x 5 = 25 x 6 = 150 so after that you would divide 150/15 which is 10! Okay so pretty much after that you would say "one cubic foot would be 10"
I hope this helps!
To find the volume of the average stone, you need to multiply its length, height, and depth.
Given that the rectangular prism stone has dimensions of 5 feet long, 5 feet high, and 6 feet deep, the volume can be calculated as follows:
Volume = length × height × depth = 5 ft × 5 ft × 6 ft = 150 ft³
Thus, the volume of the average stone is 150 cubic feet.
To find out how much one cubic foot of the stone weighs, you can divide the total weight of the stone by its volume.
Given that the stone weighs 15 tons, we need to convert it to pounds first, as weight is typically measured in pounds per cubic foot.
1 ton = 2000 pounds
So, the total weight of the stone can be calculated as:
Weight = 15 tons × 2000 pounds/ton = 30,000 pounds
Now, divide the weight of the stone by its volume to find the weight per cubic foot:
Weight per cubic foot = 30,000 pounds ÷ 150 ft³ = 200 pounds/ft³
Therefore, one cubic foot of the stone weighs 200 pounds.