Is this right?
When a 5 kg box is lifted 3 meters from the ground, calculate the gravitational potential energy stored in the box. Calculate the work done by a Force to lift the box at a constant speed. Compare this answer to the amount of gravitational potential energy stored in the box. What conclusions can you draw from this? What would happen if you did more work lifting the box than what was stored as gravitational potential energy?
ΔUg= mg Δy
ΔUg= (5kg)(-9.8 m/s^2)(3m)
ΔUg= -147J ( gravitational potential energy)
Calculate work:
W= F * D
= (5kg)(-9.8 m/s^2)
=-49 J
What happened to the distance part of your work eq?
To calculate the gravitational potential energy stored in the box, you can use the formula:
ΔUg= mgh
where ΔUg is the change in gravitational potential energy, m is the mass of the box, g is the acceleration due to gravity, and h is the height from the ground.
Therefore, to calculate the gravitational potential energy stored in the box, you can use the formula:
ΔUg = (5 kg)(9.8 m/s^2)(3 m)
ΔUg = 147 J
So, the gravitational potential energy stored in the box is 147 Joules.
To calculate the work done by a force to lift the box at a constant speed, you can use the formula:
W = Fd
where W is the work done, F is the force applied, and d is the distance moved.
Assuming the force applied is equal to the weight of the box (mg), and the distance moved is also 3 meters, the work done can be calculated as:
W = (5 kg)(9.8 m/s^2)(3 m)
W = 147 J
Therefore, the work done by the force to lift the box at a constant speed is also 147 Joules.
Comparing the amount of work done (147 J) to the amount of gravitational potential energy stored (147 J), we can conclude that they are the same. This means that the work done by the force is equal to the gravitational potential energy stored in the box.
If you were to do more work lifting the box than the amount stored as gravitational potential energy, then the extra work would be converted into another form of energy, such as kinetic energy or heat. The excess work would not contribute to the gravitational potential energy of the box.