a) how many moles of atoms are in 1 mole of Ca3(PO3)2

b)If I have 1 mole of Ca3(PO3)2, how many moles of PO3^3- ions do I have?
c)How many individual PO3^3- ions do I have?

You use the subscripts to tell you.I will assume you made a typo and you meant to type in Ca3(PO4)2 but the instructions are the same for Ca3(PO3)2.

If you have 1 mol Ca3(PO4)2 you have 6.02E23 molecules of Ca3(PO4)2.
You have 3 mols of Ca ions, 2 of P, 12 of O and 3 of PO4^3-.

It wasn't a typo. It is (PO3)2

So you are saying it should be
a) 11 moles of atoms
b) 1 mole of PO3^3- ions
c) 2 ions of PO3^3- ions (because of the subscript 2 that follows (PO3)2)

Almost.

a. Yes, 11 mols of atoms (3 Ca, 2P, 6O = 11 total)
b. You have 2 mols PO3^2- (that subscript of 2 after the closed parentheses says 2.
c. I think c is asking for individual PO3^3-, which I missed the first time around. That means you have 6.02E23 ions in 1 mol so twice that for two mols.

Nice Gary

a) To find the number of moles of atoms in 1 mole of Ca3(PO3)2, we need to first determine the number of atoms in the formula.

Ca3(PO3)2 contains 3 calcium atoms (Ca), 2 phosphorus atoms (P), and 8 oxygen atoms (O).

Therefore, the total number of atoms in the formula is 3 + 2 + (8 x 2) = 21.

Since 1 mole of any substance contains Avogadro's number of particles (6.022 x 10^23), 1 mole of Ca3(PO3)2 contains 21 x (6.022 x 10^23) atoms.

Therefore, the answer is 1 mole of Ca3(PO3)2 contains 1.264 x 10^25 atoms.

b) To determine the number of moles of PO3^3- ions in 1 mole of Ca3(PO3)2, we need to focus on the phosphate (PO3^3-) portion of the formula.

Looking at the formula, we see that there are 2 phosphate ions (PO3^3-).

Thus, 1 mole of Ca3(PO3)2 contains 2 moles of PO3^3- ions.

c) To find the number of individual PO3^3- ions in 1 mole of Ca3(PO3)2, we need to know that each PO3^3- ion consists of 3 oxygen atoms bonded to a central phosphorus atom.

In the formula, we have 2 phosphate ions (PO3^3-), so we multiply this by the number of oxygen atoms in each ion (3) to find the total number of oxygen atoms in the compound.

2 phosphate ions x 3 oxygen atoms per ion = 6 oxygen atoms.

Therefore, in 1 mole of Ca3(PO3)2, we have 6 individual PO3^3- ions.