1^2+2^2+3^2+......+10^10

when it divided by 5 what the remainder????
even a hint can,t help me my head is fried have been do math alday just show me the working i beg!

Do you have a typo?

your first 3 terms have exponents of 2, but the last term is 10^10.
I will assume it is to be 10^2

sum of all squares up to n terms
= n(n+1)(2n+1)/6
so if n = 10,
sum = 10(11)(21)/6 = 385
which when divided by 5 leaves a remainder of zero