A coin is tossed 3 times and let X be the number of heads appearing. The probability that 1 head will appear iS?

0.375

To find the probability that 1 head will appear, we need to determine the number of ways that we can get exactly 1 head out of 3 tosses.

When tossing a coin, we have two possible outcomes: heads (H) or tails (T). Since each toss is independent, we can represent the outcomes of the three tosses using a sample space.

The sample space for 3 coin tosses is:
HHH, HHT, HTH, THH, HTT, THT, TTH, TTT

Out of these 8 possible outcomes, we can see that there are 3 outcomes where exactly 1 head appears: HHT, HTH, and THH.

Therefore, the number of ways to get exactly 1 head out of 3 tosses is 3.

To calculate the probability, we divide the number of favorable outcomes (1 head) by the total number of possible outcomes (3 tosses):

Probability of getting 1 head = Number of favorable outcomes / Total number of possible outcomes
= 3 / 8

Hence, the probability that 1 head will appear when a coin is tossed 3 times is 3/8 or 0.375.