Tɨċҡɛts tօ a ʍɨɖɖʟɛ sċɦօօʟ sօċċɛʀ ɢaʍɛ ċօsts $4 ʄօʀ ċɦɨʟɖʀɛռ aռɖ $5 ʄօʀ aɖʊʟts . tɦɛ tօtaʟ ʀɛʋɛռʊɛ ʄʀօʍ tɦɛ ʀɨċҡɛts sօʟɖ աas $955. Tɦɛʀɛ աas 220 tօtaʟ tɨċҡɛts sօʟɖ . ɦօա ʍaռʏ ċɦɨʟɖʀɛռ's tɨċҡɛts աɛʀɛ sօʟɖ ?
Holy smoke! Did you do all those special characters by hand?!?!?
a+c = 220
5a+4c = 955
Now just solve for a and c.
To find out how many children's tickets were sold, we can set up a system of equations. Let's assign variables to represent the number of children's tickets and the number of adult tickets.
Let's say the number of children's tickets sold is represented by the variable 'c', and the number of adult tickets sold is represented by the variable 'a'.
According to the given information:
1) The cost of a child's ticket is $4, so the total revenue from selling children's tickets is 4c.
2) The cost of an adult ticket is $5, so the total revenue from selling adult tickets is 5a.
3) The total revenue from both children's and adult tickets is $955.
Therefore, the equation would be:
4c + 5a = 955 ----- (Equation 1)
Additionally, it is given that the total number of tickets sold is 220.
Therefore, the equation would be:
c + a = 220 ----- (Equation 2)
Now, we need to solve this system of equations to find the value of 'c', which represents the number of children's tickets sold.
To solve Equation 2 for 'a', rearrange the equation as:
a = 220 - c
Next, substitute this value of 'a' into Equation 1:
4c + 5(220 - c) = 955
Simplify the equation:
4c + 1100 - 5c = 955
1100 - 955 = 5c - 4c
145 = c
Therefore, the value of 'c', which represents the number of children's tickets sold, is 145. Hence, 145 children's tickets were sold.