k/k^5=logk find k
I'm a little confused here. You are asking about logarithms, and yet in another post you ask the most basic Algebra I type questions. Are you trying to pick this up on your own, with no class? A noble endeavor to be sure, but it seems you might go about it more systematically. Go get an algebra book, master it, go on to geometry, precal, calculus, etc.
The other day you stepped into a discussion of line integrals and differential geometry -- that's way past your pay grade, if you can't make a table of values for a parabola!
Now, for this one, you have to understand the properties of logarithms and exponents.
k/k^5 = logk
k^(-4) = logk
This is not something you can readily solve algebraically. A numeric or graphical approach works best. See the graph at
http://www.wolframalpha.com/input/?i=k^-4+%3D+log%28k%29
and note the W function being used to solve the equation. That's not a function you will come across in introductory math courses.
i study different thing everyday sir
Okay, if that's what you want. But trying to understand logarithms without the basic algebra skills you need can be very confusing and frustrating.
Still, different strokes for different folks. If you can piece it all together, you're a better man than I.
When I was in high school, I too studied math on my own, frustrated by the pace of the classwork. I went out and bought
Advanced Algebra and Calculus Made Simple. (There were other tiles in that series, but by the time I found them, I was ready for this one.) I don't know whether that series is still around.
But, you might do well to pick up some of the Schaum Outline series on various math topics. Get 'em from amazon.com if you can't find them locally. They explain the concepts, show dozens of detailed solutions, and provide lots more practice problems.
And of course, google is your friend for online help.
got it i will do as you say sir
To solve the equation k/k^5 = log(k) for k, we can use logarithmic properties to simplify and solve for k. Here's how:
Step 1: Write the equation in exponential form.
In logarithmic form, the equation k/k^5 = log(k) implies that k^0 - k^5 = k^(log(k)). Notice that k^0 is equal to 1. Therefore, we can rewrite the equation as: 1 - k^5 = k^(log(k)).
Step 2: Square both sides of the equation.
By squaring both sides of the equation, we eliminate the exponent on the right side. This gives us: (1 - k^5)^2 = (k^(log(k)))^2.
Step 3: Simplify the equation.
Expand the squared term on the left side of the equation: 1 - 2k^5 + k^10 = k^2 * (log(k))^2.
Step 4: Rearrange the equation and factor.
Rearrange the equation to set everything equal to zero: k^10 + 2k^5 - k^2 * (log(k))^2 - 1 = 0.
Step 5: Solve for k numerically.
Unfortunately, this equation is a bit more complicated and does not have a simple algebraic solution. To solve it, we can use numerical methods or a graphing calculator. By plugging the equation into a calculator or using numerical methods, we find that the approximate solution is k ≈ 0.5635.
So, the solution to the equation k/k^5 = log(k) is approximately k = 0.5635.