A chemist reacted 0.05 moles of solid sodium with water to form 50 cm3 of sodium hydroxide solution what mass of sodium was reacted?
g NaOH = mols NaOH x atomic mass Na = ?
A chemist reacts 0.05 moles of solid sodium with water to make sodium hydroxide what mass of sodium was reacted ?
To calculate the mass of sodium reacted, we need to use the molar mass of sodium (Na) and the number of moles.
The molar mass of sodium (Na) is 22.99 g/mol.
Given:
Number of moles of sodium (Na) = 0.05 moles
Now, we can calculate the mass of sodium:
Mass of sodium (g) = Number of moles × Molar mass
Mass of sodium (g) = 0.05 moles × 22.99 g/mol
Mass of sodium (g) = 1.15 g
Therefore, the mass of sodium that reacted is 1.15 g.
To find the mass of sodium that was reacted, we need to use the balanced chemical equation for the reaction between sodium and water. The balanced equation is:
2Na + 2H2O -> 2NaOH + H2
From this equation, we can see that two moles of sodium react with two moles of water to produce two moles of sodium hydroxide and one mole of hydrogen gas.
Given that 0.05 moles of sodium reacted, we can calculate the molar mass of sodium (Na) by adding up the atomic masses. The atomic mass of sodium is approximately 23 g/mol.
So, the mass of sodium reacted can be calculated as follows:
Mass of sodium reacted = Number of moles of sodium x Molar mass of sodium
= 0.05 moles x 23 g/mol
= 1.15 grams.
Therefore, the mass of sodium that was reacted in this chemical reaction is 1.15 grams.