Consider an isomeric mixture of alkenes of molar mass M=70g/mol. Determine the molecular formula of the alkenes.
Hyrogenation of the isomeric mixture produces alkanes. What is the name of the alkane.
If the alkenes in the original mixture are in equimolar proportions what is the mole composition of the alkanes obtained in the above part.
HELP PLEASE THE LAST PART OF THE QUESTION I DIDN'T UNDERSTAND
C5H10 is correct for the alkene. The alkane will be C5H12 or pentane, isopentane, or neopentane.
Wouldn't the alkanes be there in equimolar proportions; i.e., the mole fraction would be 0.5.
the molecular formula i think it C5H10
To determine the molecular formula of the alkenes in the isomeric mixture, we need to know the molar mass of each alkene in the mixture. Since the molar mass of the mixture is given as M = 70 g/mol, we cannot directly determine the molecular formula without additional information.
The name of the alkane produced by hydrogenation of the isomeric mixture cannot be determined without knowing the structure of the alkenes present in the mixture.
Regarding the last part of the question, if the alkenes in the original mixture are in equimolar proportions, it means that each alkene is present in the same quantity or mole ratio.
The mole composition of the alkanes obtained after the hydrogenation process would depend on the molecular structure of the alkenes. Without that information, we cannot determine the specific mole composition of the alkanes produced.
To determine the molecular formula of the alkenes in the isomeric mixture, we need to consider their molar mass. Given that the molar mass (M) is 70 g/mol, we can write down the possible molecular formulas of alkenes.
The general formula for an alkene is CnH2n, where n represents the number of carbon atoms in the molecule. Since the molar mass is 70 g/mol, the molecular formulas of the alkenes can be:
C3H6 (n = 3)
C4H8 (n = 4)
C5H10 (n = 5)
C6H12 (n = 6)
and so on...
Now, let's move on to the hydrogenation of the isomeric mixture. When alkenes undergo hydrogenation, they are converted to alkanes. The reaction involves the addition of hydrogen gas (H2) to the alkene double bond, producing a single bond between the carbon atoms and saturating the molecule.
Since the question doesn't provide additional information, we cannot determine the specific name of the alkane produced. However, we can describe it generically as a saturated hydrocarbon with the formula CnH2n+2. The specific name would depend on the number of carbon atoms in the alkane, which we haven't been given.
Regarding the mole composition of the alkanes obtained, it states that the alkenes in the original mixture are in equimolar proportions. This means that each alkene has an equal number of moles. Since we don't know the specific molecular formulas of the alkenes, we can't determine the exact mole composition of the alkanes produced. All we can say is that the alkanes will also have an equal number of moles.
If you have additional information or clarification on the question, please provide it so that I can assist you further.