a box contains seven red marbles, five green marbles & eight blue marble. a marble is drawn at random & is replaced. a second marble is then draw from the jar. find the probabilty that both marbles are green
What part of my answer to your almost identical question about 2 hours ago did you no like ?
Could you not make that minuscule adjustment?
http://www.jiskha.com/display.cgi?id=1458258526
second half is if both marbles are green
and ..... ???
To find the probability that both marbles drawn are green, we need to calculate the probability of drawing a green marble on the first draw and then drawing another green marble on the second draw, given that the first marble was replaced.
Step 1: Find the probability of drawing a green marble on the first draw.
The total number of marbles in the box is 7(red) + 5(green) + 8(blue) = 20. The probability of drawing a green marble on the first draw is the number of green marbles divided by the total number of marbles: 5/20 = 1/4.
Step 2: Since the first marble is replaced, the probability of drawing a green marble on the second draw is still 1/4. This is because each draw is independent, and replacing the first marble restores the original probabilities.
Step 3: Multiply the probabilities of the individual events to find the probability of both events occurring. Therefore, the probability of drawing a green marble on both the first and second draw is (1/4) * (1/4) = 1/16.
So, the probability that both marbles drawn are green is 1/16.