Suppose a vector v has initial point (4, -3) and terminal point (8, -1). Find the magnitude of v
To find the magnitude of vector v, we can use the distance formula between the initial and terminal points of the vector.
The distance formula is given by:
d = √((x2 - x1)^2 + (y2 - y1)^2)
Where (x1, y1) is the initial point and (x2, y2) is the terminal point.
In this case, the initial point is (4, -3) and the terminal point is (8, -1).
Using the distance formula, we can calculate the magnitude of v as follows:
d = √((8 - 4)^2 + (-1 - (-3))^2)
= √(4^2 + (2)^2)
= √(16 + 4)
= √20
= 4.47
Therefore, the magnitude of vector v is approximately 4.47.
To find the magnitude of a vector, you can use the distance formula. The distance formula in two dimensions is given by:
d = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, the initial point of the vector is (4, -3) and the terminal point is (8, -1).
Substituting these values into the distance formula, we get:
d = √((8 - 4)^2 + (-1 - (-3))^2)
= √((4)^2 + (2)^2)
= √(16 + 4)
= √20
= 2√5
Therefore, the magnitude of vector v is 2√5.