the temperature of 500g of a certain metal is raised to 100 degre celcius and it is then placed in 200g of water at 15 degre celcius.if the final steady temperature raises to 21 degre celcius,calculate the specific heat capacity of the metal
how is it 125 plz
The Answer is 127 J/kg°C.
mc(Tf-Ti) water + mc(Tf-Ti) metal = 0
the only unknown is the c of the metal (you can look up c for water)
125
I need the answer of this
The temperature of 500g of a certain metal is raised to 100degre celcius and it is then placed in 200g of water at 15 degre celcius .
If the final stead temperature is 21 degre celcius .find the specific heat capacity