What is the mass of MgCl2 required to make 500mL if 1.200 M of MgCl2 Solution?
I'm having trouble figuring out what the equation looks like. I believe the answer is 57.127g but if so i would like to know why.
I did (1.200M*.500mL)/1000* mass of MgCl2.
How do i find how many liters are in 1.2M of MgCl2?
To find the mass of MgCl2 required to make a 500 mL solution with a concentration of 1.200 M, you need to use the equation:
Molarity (M) = moles of solute / liters of solution
By rearranging this equation, you can solve for the moles of solute:
moles of solute = Molarity (M) * liters of solution
To find the moles of MgCl2 needed, you need to convert the volume of the solution from milliliters (mL) to liters (L). To do this, divide 500 mL by 1000:
Liters of solution = 500 mL / 1000 = 0.500 L
Now you can calculate the moles of MgCl2 required:
moles of MgCl2 = 1.200 M * 0.500 L = 0.600 moles
To find the mass of MgCl2 required, you need to use the molar mass of MgCl2, which you can find by adding up the atomic masses of magnesium (Mg) and chlorine (Cl). The atomic mass of Mg is approximately 24.31 g/mol, and the atomic mass of Cl is approximately 35.45 g/mol.
Molar mass of MgCl2 = (1 * atomic mass of Mg) + (2 * atomic mass of Cl) = (1 * 24.31 g/mol) + (2 * 35.45 g/mol) = 95.21 g/mol
Finally, you can calculate the mass of MgCl2 required:
mass of MgCl2 = moles of MgCl2 * molar mass of MgCl2 = 0.600 moles * 95.21 g/mol = 57.127 g
Therefore, the correct answer is 57.127 g.
To summarize, you correctly calculated the moles of MgCl2 needed, but you made a mistake in converting mL to L. Instead of multiplying by the mass of MgCl2, you need to use the molar mass to convert moles to grams.
To find the mass of MgCl2 required to make 500 mL of a 1.200 M solution, you need to use the equation:
Molarity (M) = moles of solute / liters of solution
To find the number of moles of MgCl2, we need to rearrange the equation:
moles of solute = Molarity (M) x liters of solution
First, convert the milliliters to liters by dividing by 1000:
500 mL / 1000 = 0.5 L
Now, substitute the values into the equation:
moles of solute = 1.200 M x 0.5 L
moles of solute = 0.6 moles
Next, you need to find the molar mass of MgCl2. The molar mass of Mg is 24.31 g/mol, and the molar mass of Cl is 35.45 g/mol.
Molar mass of MgCl2 = (24.31 g/mol) + 2(35.45 g/mol)
= 95.21 g/mol
Finally, calculate the mass of MgCl2:
mass of MgCl2 = moles of solute x molar mass of MgCl2
= 0.6 moles x 95.21 g/mol
= 57.127 g
So, your calculation of 57.127 g for the mass of MgCl2 is correct.