If a parallelogram has a base of 13 mm and an area of 78 mm2 what is the height?
78/13 = 6
H = 6mm
Is the average of the two bases 13 mm?
If so, you're right.
To find the height of a parallelogram, you need to know its base and area. In this case, the base of the parallelogram is given as 13 mm, and the area is given as 78 mm^2.
To find the height, you can use the formula for the area of a parallelogram:
Area = Base × Height
Rearranging the formula, we can solve for the height:
Height = Area / Base
Plugging in the values, we get:
Height = 78 mm^2 / 13 mm
Simplifying the expression, we find:
Height = 6 mm
So, the height of the parallelogram is 6 mm.
To find the height of a parallelogram, you need to divide its area by the length of its base. The formula for finding the area of a parallelogram is A = base * height. In this case, you have the area (78 mm^2) and the length of the base (13 mm). So, by rearranging the formula, you can solve for the height:
A = base * height
78 = 13 * height
To isolate the height, divide both sides of the equation by the length of the base:
78 / 13 = height
By calculating, you get:
height = 6 mm
Therefore, the height of the parallelogram is 6 mm.