what volume will 5.00g of nitrous oxide gas occupy at 50 degree celcius and 4.00L?
Huh? Are you saying that it will occupy 4.00L?
Then that is its volume.
Please fix the problem. and recall that PV/T is constant.
To determine the volume that 5.00g of nitrous oxide gas will occupy at 50 degrees Celsius and 4.00L, we need to use the ideal gas law equation: PV = nRT.
Here's how you can calculate it step by step:
1. Convert the temperature from Celsius to Kelvin:
T(K) = t(°C) + 273.15
T(K) = 50 + 273.15 = 323.15 K
2. Convert the mass of nitrous oxide gas to moles:
Moles (n) = Mass (m) / Molar mass (M)
The molar mass of nitrous oxide (N2O) is determined by summing the atomic masses of its constituent elements:
Molar mass (N2O) = (2 x Atomic mass of Nitrogen) + Atomic mass of Oxygen
Molar mass (N2O) = (2 x 14.01 g/mol) + 16.00 g/mol = 44.01 g/mol
Moles (n) = 5.00 g / 44.01 g/mol = 0.1136 mol
3. Plug the values into the ideal gas law equation:
PV = nRT
P(4.00L) = (0.1136 mol)(0.0821 L·atm/mol·K)(323.15 K)
4. Solve for the pressure (P):
P = (0.1136 mol)(0.0821 L·atm/mol·K)(323.15 K) / 4.00 L
P = 2.06 atm
So, 5.00g of nitrous oxide gas will occupy approximately 2.06 atm at 50 degrees Celsius and a volume of 4.00L.