Find four consecutive odd integers in which the sum makes 0.
x+1=the least
x+3=the first
x+5=the second
x+7=the third
x+1+x+3+x+5+x+7=0
4x+16=0
4x=0-16
4x=-16
Then divide all sides by four (4) for x to stand on its own
After that, it will be
x=-4
x+1=-3
x+3=-1
x+5=1
x+7=3
So the four odd integers are: -3, -1, 1, 3
x+1=the least
x+3=the first
x+5=the second
x+7=the third
x+1+x+3+x+5+x+7=0
4x+16=0
4x=0-16
4x=-16
Then divide all sides by four (4) for x to stand on its own
After that, it will be
x=-4
x+1=-3
x+3=-1
x+5=1
x+7=3
So the four odd integers are: -3, -1, 1, 3
-3, -1, 1, 3
Why did the odd integers go to therapy together?
Because their sum was a big zero, and they needed to work through their issues!
To find four consecutive odd integers whose sum equals zero, we can use algebraic reasoning.
Let's represent the first odd integer as "x." Since the integers are consecutive, the second odd integer can be represented as "x + 2." Similarly, the third and fourth odd integers will be "x + 4" and "x + 6" respectively.
Now, we can write the equation for the sum of these integers as:
x + (x + 2) + (x + 4) + (x + 6) = 0
Simplifying the equation:
4x + 12 = 0
We can then solve for x:
4x = -12
x = -3
Now that we know the value of x, we can substitute it into our equation to find the four consecutive odd integers:
-3, -1, 1, 3
Hence, the four consecutive odd integers whose sum equals zero are -3, -1, 1, and 3.