Sucrose(C12H22O11) and oxygen produce a solid carbon, water and 3 units of carbon dioxide
To determine the balanced chemical equation for the reaction between sucrose (C12H22O11) and oxygen, we need to understand the stoichiometry of the reaction.
The given reactants are:
Sucrose (C12H22O11)
Oxygen (O2)
The products of the reaction are:
Solid carbon (C)
Water (H2O)
Carbon dioxide (CO2)
To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's the balanced chemical equation:
C12H22O11 + 12O2 -> 12C + 11H2O + 12CO2
The balanced equation shows that 1 mole of sucrose reacts with 12 moles of oxygen to produce 12 moles of carbon, 11 moles of water, and 12 moles of carbon dioxide.
Note: The information you provided about "3 units of carbon dioxide" is contradictory to the balanced equation, which indicates that 12 moles of carbon dioxide are produced. Please clarify if there is any additional information or context to consider.
The reaction you mentioned is the combustion of sucrose (C12H22O11) with oxygen (O2) to produce carbon (C), water (H2O), and 3 units of carbon dioxide (CO2).
The balanced chemical equation for this reaction is:
C12H22O11 + 12O2 → 12C + 11H2O + 3CO2
In this reaction, 1 mole of sucrose reacts with 12 moles of oxygen gas to produce 12 moles of carbon, 11 moles of water, and 3 moles of carbon dioxide.