Boyle's Law says that the volume of a gas varies inversely with the pressure. When the volume of a certain gas is 5 liters, the pressure is 158 kPa (kilopascals). What is the volume when the pressure is 395 kPa?
then
V = k/p
for the given:
5 = k/158
k = 790
or
V = 790/p
for p = 395
V = 790/395 = 2
To solve this problem, we can use Boyle's Law, which states that the volume of a gas varies inversely with the pressure.
Boyle's Law equation is given by:
P1 * V1 = P2 * V2
Where:
P1 = initial pressure
V1 = initial volume
P2 = final pressure
V2 = final volume
We are given:
P1 = 158 kPa
V1 = 5 liters
P2 = 395 kPa (kilopascals)
Let's substitute these values into the Boyle's Law equation and solve for V2:
P1 * V1 = P2 * V2
158 kPa * 5 liters = 395 kPa * V2
790 kPa * liters = 395 kPa * V2
To isolate V2, divide both sides of the equation by 395 kPa:
V2 = (790 kPa * liters) / 395 kPa
Simplifying the expression:
V2 = 2 liters
Therefore, when the pressure is 395 kPa, the volume of the gas is 2 liters.
To solve this problem, we can use Boyle's Law which states that the volume of a gas varies inversely with the pressure. Mathematically, it can be expressed as:
P₁V₁ = P₂V₂
Where P₁ and V₁ are the initial pressure and volume, and P₂ and V₂ are the final pressure and volume.
Given that the initial volume (V₁) is 5 liters and the initial pressure (P₁) is 158 kPa, we can substitute these values into the equation:
158 kPa * 5 liters = 395 kPa * V₂
Simplifying this equation, we get:
790 kPa liters = 395 kPa * V₂
Dividing both sides of the equation by 395 kPa:
(790 kPa liters) / 395 kPa = V₂
So, the volume (V₂) when the pressure is 395 kPa is 2 liters.