Each pail of plaster covers 90 square feet of ceiling. What is the least number of pails of plaster you would need to buy to cover the ceiling of a room with walls 14 feet long? 5 pails

6 pails*****
4 pails
3 pails

3 pails.

thx its three

To find the least number of pails of plaster needed to cover the ceiling of a room with walls 14 feet long, we need to determine the total area of the ceiling and then divide it by the coverage of each pail.

The total area of the ceiling can be calculated by multiplying the length by the width. In this case, the width is not given, so we assume it to be the same as the length of the walls, which is 14 feet.

Total ceiling area = length × width = 14 feet × 14 feet = 196 square feet

Since each pail of plaster covers 90 square feet, we divide the total ceiling area by the coverage of each pail to find the number of pails needed:

Number of pails = Total ceiling area / Coverage per pail = 196 square feet / 90 square feet = 2.1778 (approx.)

Since we cannot purchase a fraction of a pail, we need to round up the number of pails to the nearest whole number. Therefore, the least number of pails of plaster needed to cover the ceiling is 3 pails.

So, the correct answer is 3 pails, not 6 pails.

Assuming the ceiling is a square

Area of square = L*W

L*W = 14ft * 14ft = 196ft^2

Area/90ft^2 =?

its 3 not 6

Thanks, you guys!