Write a balanced chemical equation for this:
The RXN of hydronium ion with solid calcium carbonate to form calcium and bicarbonate (HCO3-) ions.
To write a balanced chemical equation for this reaction, we first need to identify the reactants and products involved.
Reactants:
1. Hydronium ion (H3O+)
2. Calcium carbonate (CaCO3)
Products:
1. Calcium ion (Ca2+)
2. Bicarbonate ion (HCO3-)
Now, let's write the chemical equation:
H3O+ + CaCO3 -> Ca2+ + HCO3-
To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.
Let's start by balancing the calcium (Ca) atoms. There is only one calcium atom on the left side, so we will place a coefficient of 1 in front of CaCO3:
H3O+ + 1CaCO3 -> Ca2+ + HCO3-
Next, let's balance the hydrogen (H) atoms. There are three hydrogen atoms in the hydronium ion on the left side, so we will place a coefficient of 3 in front of H3O+:
3H3O+ + CaCO3 -> Ca2+ + HCO3-
Lastly, let's balance the oxygen (O) atoms. On the left side, there are three oxygen atoms in the carbonate ion (CO3^2-). However, on the right side, we have only one oxygen atom in the bicarbonate ion. To balance the oxygen atoms, we need to multiply the bicarbonate ion by 3:
3H3O+ + CaCO3 -> Ca2+ + 3HCO3-
Now, the equation is balanced:
3H3O+ + CaCO3 -> Ca2+ + 3HCO3-