Create a visually engaging diagram illustrating the chemical process of neutralization. Show a balance scale with two plates. On the left plate, depict 50 gram of sulfuric acid (H2SO4) represented as shiny, spherical molecules. Each molecule should be built of two hydrogen atoms (small circles), one sulfur atom (large circle), and four oxygen atoms (medium circles). On the right plate, indicate the needed amount of sodium hydroxide (NaOH) to balance the scale, represented by cubes. Each cube should be composed of one sodium atom (large), one oxygen atom (medium), and one hydrogen atom (small). Don't include any text.

how many grams of NaOH are needed to neutralize 50 grams of H2SO4?

NaOH+H2SO4=Na2SO4+H2O

2NaOH+H2SO4=Na2SO4+2H2O
X/80=50/98
X=40.81g

H2SO4 + 2NaOH ==> Na2SO4 + 2H2O

mols H2SO4 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols H2SO4 to mols NaOH.
Then g NaOH = mols NaOH x molar mass NaOH = ?

2NaOH+H2SO4=Na2SO4+2H2O-----balanced equation

x/80=50/98.6
x=80*50/98.6
x=40.56

2NaOH+ H2So4= NaSo4+2H2o

40.81

41.81

2Naoh+h2so4 na2so4+2h2o

50g/100g=x/98g
X=98g×50g/100g
X=49g

40.89

How many grams of NaOH are needed to neutralize 50 grams of H2So4?

H2SO4+2NaOH->Na2So4+2H20

50/98=X/80
X=40.81

40.81