Calcium carbonate, CaCO3, when heated decomposes to calcium oxide and carbon dioxide. Calulate the mass of clacium oxide formed when 2.0 grams of CaCO3 is decomposed.
To calculate the mass of calcium oxide (CaO) formed when 2.0 grams of calcium carbonate (CaCO3) is decomposed, you need to consider the molar masses of each compound and the balanced chemical equation for the reaction.
The molar mass of CaCO3 = 40.08 g/mol (Ca) + 12.01 g/mol (C) + 3(16.00 g/mol) (O)
= 40.08 g/mol + 12.01 g/mol + 48.0 g/mol
= 100.09 g/mol
From the balanced chemical equation for the reaction:
CaCO3 -> CaO + CO2
The ratio of CaCO3 to CaO is 1:1, meaning 1 mole of CaCO3 produces 1 mole of CaO.
To find the moles of CaCO3, you can use the formula:
Moles = mass / molar mass
Moles of CaCO3 = 2.0 g / 100.09 g/mol
= 0.01999 mol (approximately 0.02 mol)
Since the ratio of CaCO3 to CaO is 1:1, the moles of CaO formed will also be approximately 0.02 mol.
Now, to find the mass of CaO, you can use the formula:
Mass = moles x molar mass
Mass of CaO = 0.02 mol x 56.08 g/mol (molar mass of CaO)
= 1.1216 g (approximately 1.12 g)
Therefore, approximately 1.12 grams of calcium oxide (CaO) will be formed when 2.0 grams of calcium carbonate (CaCO3) is decomposed.
To calculate the mass of calcium oxide formed when 2.0 grams of CaCO3 is decomposed, you need to use the molar masses of the compounds involved.
First, let's find the molar mass of calcium carbonate (CaCO3):
Molar mass of Ca = 40.08 g/mol
Molar mass of C = 12.01 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of CaCO3 = (1 x 40.08) + (1 x 12.01) + (3 x 16.00) = 100.09 g/mol
The balanced chemical equation for the decomposition of calcium carbonate is:
CaCO3 --> CaO + CO2
According to the equation, 1 mole of CaCO3 produces 1 mole of CaO.
So, the ratio between the molar masses of CaO and CaCO3 is 1:1.
Now, let's calculate the moles of CaCO3:
Moles of CaCO3 = Mass of CaCO3 / Molar mass of CaCO3
Moles of CaCO3 = 2.0 g / 100.09 g/mol ≈ 0.020 mol
Since the molar ratio of CaO to CaCO3 is 1:1, the moles of CaO produced will also be 0.020 mol.
Finally, let's calculate the mass of CaO:
Mass of CaO = Moles of CaO x Molar mass of CaO
Mass of CaO = 0.020 mol x 56.08 g/mol = 1.12 g
Therefore, when 2.0 grams of CaCO3 is decomposed, approximately 1.12 grams of calcium oxide will be formed.