A man is holding a gun 4 feet above the ground and fires into an open field. The bullet has an initial velocity of 300 feet per second and an initial angle of 30°. Find the range (the horizontal distance traveled before hitting the ground ) and the bullet's max height. Please show.

h(t)= h0 + vo t sinθ - 16t^2

man, you have the equation. As you know the parabola

h = at^2 + bt + c

has its vertex at t = -b/2a

So, just plug and chug.

As for the range, find t when h=0 and then recall that the (constant) horizontal velocity is

vo cosθ