Mole calculations:

How much does 2.5 x 10^24 molecules of p2o3 weigh ?

weight? or mass.

mass=numbermoles*molmass
= 2.5E24/6.02E23* (2*31+3*16)g

Which is greater? 25.0 grams of calcium OR 2.5 x10^24 atoms of calcium (Prove It)

Pls help me. Calculate the number of moles of calcium chloride(cacl2),that can be obtain from 25kg of limestone(caco3) in the presence of excess of HCL.(ca=40, c=12, O=16, H=1, cl=35.5)

To calculate the weight of a given number of molecules, we need to first determine the molar mass of the compound. In this case, we have P2O3, which consists of two phosphorus atoms (P) and three oxygen atoms (O).

To find the molar mass of P2O3, we need to multiply the atomic mass of each element by the number of atoms present and then add them together. The atomic mass of phosphorus (P) is approximately 31.0 g/mol, and the atomic mass of oxygen (O) is approximately 16.0 g/mol.

(2 * 31.0 g/mol) + (3 * 16.0 g/mol) = 62.0 g/mol + 48.0 g/mol = 110.0 g/mol

Now that we have the molar mass of P2O3, we can calculate the weight of 2.5 x 10^24 molecules of P2O3 using the formula:

Weight (g) = Number of molecules x Molar mass (g/mol)

Weight (g) = (2.5 x 10^24 molecules) x (110.0 g/mol)

To get the exact calculation result, let's calculate it:

Weight (g) = 2.5 x 10^24 molecules x 110.0 g/mol

Weight (g) = 2.75 x 10^26 g

Therefore, 2.5 x 10^24 molecules of P2O3 weigh 2.75 x 10^26 grams.