s Patricia finds that the experimental

probability of her dog wanting to go outside between 4 p.m. and 5 p.m.
is 7/12. About what percent of the time does her dog not want to go out
between 4 p.m. and 5 p.m.?

time the dog wants to go outside in that time frame = (7/12)(60) = 35 minutes

so not wanting to outside = 25 minutes

percentage of time not going out
= 25/60 = appr 42%

42%

42#

To find out what percent of the time Patricia's dog does not want to go out between 4 p.m. and 5 p.m., we can subtract the experimental probability of the dog wanting to go out from 1 (since the total probability is always 1). Then, we can convert the result to a percentage.

So, the percentage of the time that the dog does not want to go out can be calculated as follows:

Percentage = (1 - Experimental Probability) x 100

In this case, the experimental probability is 7/12. So we can substitute this value into the formula:

Percentage = (1 - 7/12) x 100

To simplify the calculation, we can subtract the fractions by finding a common denominator:

Percentage = (12/12 - 7/12) x 100

Percentage = (5/12) x 100

Percentage = 500/12

To compute the actual decimal value or percentage, we divide 500 by 12:

Percentage = 41.67%

So, about 41.67% of the time Patricia's dog does not want to go out between 4 p.m. and 5 p.m.