3.05 g of hydrated copper sulphate produces 1.94g of anhydrous salt.assuming complete removal of all water of crystallization,determine the formula of hydrated copper sulfate

3.05 g CuSO4.XH20

1.95 g CuSO4
moles CuSO4=1.95/159.6=1.22E-2
grams water=difference above or
2.10 g, or moles water=2.10/18=.117

ratio moles water/salt=.117/.0122=9.6

well, X is not going to be 9.6, so round to 10.
Copper (II) sulfate decahydrate

It was good

Well, this seems like a job for Detective Clown Bot!

Let's break it down. We know that we have 3.05 grams of hydrated copper sulfate, and after removing all the water, we end up with 1.94 grams of anhydrous salt.

To find the formula of the hydrated copper sulfate, we need to determine the molar mass of the anhydrous salt and compare it to the amount of anhydrous salt we have.

The molar mass of copper sulfate (CuSO4) is:
Cu: 63.55 g/mol
S: 32.07 g/mol
4 O: 4 x 16.00 g/mol = 64.00 g/mol

Adding these up, we get a molar mass of 159.62 g/mol.

Now, let's calculate the number of moles of the anhydrous salt we have:
Number of moles = mass / molar mass
Number of moles = 1.94 g / 159.62 g/mol ≈ 0.012 mole

Since we lost water during the dehydration process, the number of moles of the anhydrous salt we have is also equal to the number of moles of hydrated copper sulfate that we started with.

So, the formula of the hydrated copper sulfate is CuSO4⋅xH2O, where x is the number of moles of water present.

To calculate the value of x, we subtract the number of moles of the anhydrous salt from the number of moles of the hydrated copper sulfate:

0.012 mole (hydrated copper sulfate) - 0.012 mole (anhydrous salt) = 0 mole

Based on this calculation, it seems that all the water has been removed and there is no water of crystallization remaining.

Therefore, the formula of the hydrated copper sulfate is CuSO4.

To determine the formula of hydrated copper sulfate, we need to calculate the number of moles of hydrated copper sulfate and the number of moles of anhydrous copper sulfate produced.

1. Calculate the number of moles of anhydrous copper sulfate:
Anhydrous copper sulfate = 1.94g / molar mass of anhydrous copper sulfate

The molar mass of anhydrous copper sulfate (CuSO4) is calculated as follows:
Molar mass of Cu = 63.55 g/mol
Molar mass of S = 32.07 g/mol
Molar mass of 4O = 4 * 16.00 g/mol

Molar mass of anhydrous copper sulfate = (63.55 + 32.07 + (4 * 16.00)) g/mol

Substituting the values, we get:
Anhydrous copper sulfate = 1.94g / (63.55 + 32.07 + (4 * 16.00)) g/mol

2. Calculate the number of moles of hydrated copper sulfate:
Hydrated copper sulfate = 3.05g / molar mass of hydrated copper sulfate

The molar mass of hydrated copper sulfate can be calculated by adding the molar mass of anhydrous copper sulfate and the molar mass of water (H2O).

The molar mass of water (H2O) is 2 * 1.01 g/mol + 16.00 g/mol.

Molar mass of hydrated copper sulfate = molar mass of anhydrous copper sulfate + molar mass of water

Substituting the values, we have:
Hydrated copper sulfate = 3.05g / (molar mass of anhydrous copper sulfate + (2 * 1.01 + 16.00)) g/mol

3. Calculate the ratio of moles between hydrated and anhydrous copper sulfate:
Ratio = moles of hydrated copper sulfate / moles of anhydrous copper sulfate

Ratio = (3.05g / (molar mass of anhydrous copper sulfate + 18.02 g/mol)) /
(1.94g / molar mass of anhydrous copper sulfate)

4. Simplify the ratio to find the formula:
The ratio will give us the number of water molecules (H2O) in each formula unit of hydrated copper sulfate.

For example, if the ratio is 5, the formula of the hydrated copper sulfate would be CuSO4 · 5H2O.

Calculate the ratio and determine the formula accordingly.

To determine the formula of hydrated copper sulfate, we need to calculate the number of moles of the hydrated copper sulfate and the number of moles of the anhydrous salt produced.

First, let's calculate the number of moles of anhydrous salt produced:
- Given mass of anhydrous salt = 1.94 g
- We can determine the number of moles using the formula: moles = mass / molar mass
- The molar mass of copper sulfate (CuSO4) is calculated as follows:
- Molar mass of Cu = 63.55 g/mol
- Molar mass of S = 32.07 g/mol
- Molar mass of four O atoms = 4 * 16.00 g/mol = 64.00 g/mol
- Adding them together: 63.55 + 32.07 + 64.00 = 159.62 g/mol
- Now, we can calculate the number of moles of anhydrous salt: moles = 1.94 g / 159.62 g/mol

Next, we need to calculate the number of moles of water in the hydrated copper sulfate by subtracting the moles of the anhydrous salt produced from the moles of the hydrated copper sulfate used:
- Given mass of hydrated copper sulfate = 3.05 g
- Moles of water = moles of hydrated copper sulfate - moles of anhydrous salt

Finally, we can determine the formula of the hydrated copper sulfate:
- The formula of hydrated copper sulfate is CuSO4·nH2O, where n represents the number of water molecules.
- To find the value of n, we need to consider the ratio of the moles of water to the moles of anhydrous salt.

With this information, we can determine the formula of hydrated copper sulfate.