john wants to get his friend, peter, to a height of 2.8 m above the ground to reach an apple in a tree. they connect a swing to a high branch in an adjacent tree. the bottom of the swing, X, is at a height of 1.2 m. peter has s mass of 45 kg. ignore the effects of any frictional forces.
calculate the minimum speed with which John needs to push peter from point X to reach the apple on the tree.
.................good luck.................
If the bottom of the swing is 1.2 meters, then his arms should easily reach up one more meter. That means the swing has to go .4 meters higher.
1/2 m v^2=mgh
v^2=2g(1.2)=2.4g
v= sqrt (of that).