what is the concentration of each substance if a solution is prepared by mixing 5.00g of NaC2H3O2 with 15.0 ml of 1.45M acetic acid and then bringing the total volume to 250.0 ml?

acetic acid = HAc

NaC2H3O2 is NaAc

mols NaAc = grams/molar mass = ?
Then mols NaAc/0.250 = ?M

mols HAc = molsL.
mols = M HAc x L HAc
volume = 0.250 L
M = mols/L.

To find the concentration of each substance in the solution, we need to break down the process and calculate step by step. Let's calculate the concentration of each substance one by one:

Step 1: Calculate the number of moles of acetic acid (CH3COOH) used.
Given:
- Volume of acetic acid = 15.0 mL
- Concentration of acetic acid = 1.45 M

Molarity (M) is defined as moles of solute per liter of solution. To find the moles of acetic acid, we need to convert the volume from mL to liters:
Volume of acetic acid = 15.0 mL = 15.0 / 1000 = 0.015 L

Now, we can use the formula: Molarity = moles / volume
1.45 M = moles of acetic acid / 0.015 L

Rearranging the formula, we can find the moles of acetic acid:
moles of acetic acid = 1.45 M × 0.015 L = 0.02175 moles

Step 2: Calculate the moles of sodium acetate (NaC2H3O2).
Given:
- Mass of NaC2H3O2 = 5.00 g
- Molar mass of NaC2H3O2 = 82.03 g/mol

Using the formula: moles = mass / molar mass, we can calculate the moles of sodium acetate:
moles of NaC2H3O2 = 5.00 g / 82.03 g/mol = 0.06091 moles

Step 3: Calculate the total moles of the final solution.
To calculate the total moles of the final solution, we need to sum up the moles of acetic acid and sodium acetate:
Total moles = moles of acetic acid + moles of sodium acetate
Total moles = 0.02175 moles + 0.06091 moles = 0.08266 moles

Step 4: Calculate the final concentration of acetic acid in the solution.
Given:
- Total volume of the solution = 250.0 mL = 250.0 / 1000 = 0.250 L

Using the formula: Molarity = moles / volume, we can calculate the final concentration of acetic acid:
Final concentration of acetic acid = 0.08266 moles / 0.250 L = 0.3306 M

Step 5: Calculate the final concentration of sodium acetate in the solution.

Using the formula: Molarity = moles / volume, we can calculate the final concentration of sodium acetate:
Final concentration of sodium acetate = 0.06091 moles / 0.250 L = 0.2436 M

Therefore, the final concentration of acetic acid in the solution is 0.3306 M, and the final concentration of sodium acetate in the solution is 0.2436 M.