The bottom of a shopping bag measures 8 inches by 10 inches. The bag has a height of 12 inches. How much paper is needed to make the bag?
1.D
2.D
3.A
4.C
Lizard is correct for you bois
Thanks guys! Lizard is right, got 100%
bottom: 9x10
two sides: 8x12
two sides: 10x12
To calculate the amount of paper needed to make the bag, we need to find the surface area of the bag.
The surface area of the bag can be calculated by finding the area of the bottom (which is a rectangle) and the areas of the four sides (which are all rectangles as well). Then, we add up these areas to get the total surface area.
Given:
Bottom dimensions: 8 inches by 10 inches.
Height of the bag: 12 inches.
To find the surface area of the bottom, we use the formula for the area of a rectangle: length x width.
Area of the bottom = 8 inches x 10 inches = 80 square inches.
Now let's calculate the area of one of the sides. The sides are all rectangles, so we will have two sides with the dimensions of 8 inches by 12 inches, and the other two sides with the dimensions of 10 inches by 12 inches.
Area of one side (8 inches by 12 inches) = 8 inches x 12 inches = 96 square inches.
Area of one side (10 inches by 12 inches) = 10 inches x 12 inches = 120 square inches.
We have four sides, so the total area of all sides is:
Total area of sides = 2 x (area of one side with dimensions 8 inches by 12 inches) + 2 x (area of one side with dimensions 10 inches by 12 inches)
= 2(96 square inches) + 2(120 square inches)
= 192 square inches + 240 square inches
= 432 square inches.
To find the total surface area, we need to add the area of the bottom to the total area of the sides:
Total surface area = Area of the bottom + Total area of sides
= 80 square inches + 432 square inches
= 512 square inches.
Therefore, to make the shopping bag, you would need 512 square inches of paper.