You take a trip by air that involves three independent flights. If there is an 72 percent chance each specific leg of the trip is on time, what is the probability all three flights arrive on time? (Round your answer to 3 decimal places.)

To find the probability that all three flights arrive on time, we need to multiply the probability of each individual flight being on time together.

Given that each specific leg of the trip has a 72 percent (or 0.72) chance of being on time, the probability of all three flights being on time can be calculated as follows:

Probability of all three flights arriving on time = (0.72) * (0.72) * (0.72)

Let's compute this:

Probability of all three flights arriving on time = 0.72 * 0.72 * 0.72 = 0.373248

Rounding this to 3 decimal places, the probability that all three flights arrive on time is approximately 0.373.

To find the probability that all three flights arrive on time, we need to multiply the probabilities of each individual flight being on time.

Given that there is a 72 percent chance each specific leg of the trip is on time, we can convert this probability to a decimal by dividing by 100:

72 percent = 72/100 = 0.72

Since the flights are independent, we can assume that the probability of all three flights being on time is the product of the individual probabilities:

Probability of all three flights being on time = 0.72 * 0.72 * 0.72

Calculating this product, we get:

0.72 * 0.72 * 0.72 = 0.373248

Rounding to 3 decimal places, the probability that all three flights arrive on time is approximately 0.373.

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