The sample space for a roll of two number cubes is shown in the table.

(1,1)|(1,2)|(1,3)|(1,4)|(1,5),(1,6)
(2,1)|(2,2)|(2,3)|(2,4)|(2,5)|(2,6)
(3,1)|(3,2)|(3,3)|(3,4)|(3,5)|(3,6)
(4,1)|(4,2)|(4,3)|(4,4)|(4,5)|(4,6)
(5,1)|(5,2)|(5,3)|(5,4)|(5,5)|(5,6)
(6,1)|(6,2)|(6,3)|(6,5)|(6,5)|(6,6) What is the probability that the roll will result in one even and one odd number?

A. 1/9
B. 1/4
C. 1/3
D. 1/2 ***

The two numbers rolled can be added to get a sum. Find P(sum is greater than 5).

A. 5/6 ***
B. 13/18
C. 2/3
D. 1/2

Please?

first one is correct

prob(sum > 5)
= 1 - prob(sum ≤ 5)
= 1 - 10/36
= 26/36
= 13/18

Don't add a new question as a reply to another post, in this case your own.
One might think it has been answered and it gets overlooked ....

Your answer to the cell phone question is correct

Bobpursley said I was wrong on the second one, I ORIGINALLY got 13/18. And, he said I got it wrong. But, I did. Click on my name, and go to "Are all answers right?" Strange, but thank you.

It said: P(sum is greater than 5)

so we have to exclude those equal or less than 5

11 12 13 14
21 22 23
31 32
41 -----> there are 10 of those, leaving 26 to be > 5

so prob(sum> 5)
= 1 - 10/36 = 26/36 = 13/18
or by using the 26 count directly
prob( sum > 5) = 26/36 = 13/18

Trust this answer, please

I trust you, too. I, too, got the same answer. But, bobpursley unexpectedly thought it was wrong or something.

Sandy, I have made many errors and mistakes.

Sometimes we read a question too quickly and miss something.
In my case I just call it a "senior moment, lol

A quality supervisor for a factory that makes cell phone cases examines a sample of 46 cases. She finds that 8 cases are the wrong size. Which is the best prediction of the number of cases that will be the wrong size in a shipment of 3,000?

A. 410
B. 475
C. 506
D. 522 ***