a car starts from rest and accelerates at 6m/s^2.how far does it travel in 3s?

To determine the distance traveled by the car in 3 seconds, we can make use of the equations of motion.

The given information indicates that the car starts from rest, which means its initial velocity (u) is 0 m/s. The car's acceleration (a) is given as 6 m/s^2, and the time (t) is 3 seconds.

To find the distance traveled (S), we can use the equation of motion:

S = ut + (1/2)at^2

Since the car starts from rest, we can simplify the equation to:

S = (1/2)at^2

Now, substitute the values into the equation:

S = (1/2) * 6 * (3^2)

Simplifying further:

S = (1/2) * 6 * 9

S = 27 meters

Therefore, the car travels a distance of 27 meters in 3 seconds.

vf^2=vi^2+ 2*acceleration*distance

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